Answer: 2 attempts. |
Many responses came with 3 attempts. See the solution below. |
Out of the 8 balls, we take 3 and 3 balls into the two pans of the balance. |
[Our mind tendency is that it divides 8 balls into two sets of 4 each, which leads to 3 attempts.] |
If the pans are balanced then the faulty ball is in the remaining 2 balls. |
With the second attempt we can figure it out. |
If the pans are not balanced then the less weighing pan is having the faulty one. |
Now out of the 3 balls in that pan, we take two and put them one in each pan. |
If they balance, then the remaining one is the faulty one. |
If not, less weighing ball is the faulty one. |
Winners:Raghu Ayinapurapu followed by Sravya Ainapurapu, Rajeswararao Ainapurapu, Sumanth Nethi. |
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