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| Answer:First cube (0,1,2,3,4,5) and second cube (0,1,2,6,7,8) where the 6 is reversible to form 9. |
| For representing numbers from 1 to 31, we use (0,1,2,3) in tens place and (0,1,2,3,…9) in units place. |
| Out of these (1,2) should be there on both cubes to form '11', '22'. |
| As we need '01', '02' ... '09' and 1 to 9 will not fit on one cube. We need to have 0 on both cubes. |
| Now we filled 6 faces (3 on first and 3 on second cube) with (0,1,2). |
| We are left with 6 more faces and required numbers being (3,4,5,6,7,8,9). |
| How can this be possible to fit 7 numbers on 6 faces? |
| The tricky part here is 'We can use 6 as 9 when reversed'. |
| Thus the two cubes will have numbers (0,1,2,3,4,5) and (0,1,2,6,7,8) respectively. |
| Winners:Raghu Ayinapurapu followed by Sravya Ainapurapu, Rajeswararao Ainapurapu, Sumanth Nethi. |
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