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| Answer:12.35%. |
| Let us assume 'b' is the base of the triangle and 'h' is the altitude of the triangle. |
| So the area of the triangle is (1/2) bh. |
| If the base is increased by 7%, the new base would be 1.07b. |
| Similarly if the altitude is increased by 5%, the new altitude would be 1.05h. |
| The new area is (1/2) (1.07b)(1.05h) = (1/2) (1.1235)bh. |
| So the increase in area = (1/2) (1.1235)bh - (1/2) bh |
| = (1/2) bh [1.1235 - 1] |
| = (1/2) bh [0.1235] |
| Percentage increase in area = [Increase in area/Original area] x 100 |
| = [(1/2) bh (0.1235)/ (1/2) bh] x 100 |
| = [0.1235] x 100 = 12.35% |
| Winners: Sravya Ainapurapu, Raghu Ayinapurapu, Rajeswararao Ainapurapu, Sumanth Nethi, |
| Bharadwaj Ainapurapu, Gampa Narasimha Murty. |
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