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| Answer:59 and 61. |
| This is very simple and easy question if we understand the requirement. |
| As we know, the LCM (Least Common Multiple) of 2,3,4,5,6 (which is 60) is divisible by all the numbers from 2 to 6. |
| To get a remainder 1 all the time when divided by number 2 to 6, we need to add 1 to the LCM. |
| So 61 is the age of second person. |
| Similarly, when 1 is subtracted from LCM, the resulting number gives a remainder 1 less than the divisor itself. |
| In our case 59 when divided by 2,3,4,5,6 gives remainders 1,2,3,4,5 respectively. |
| So 59 is the age of first person. |
| Winners:Sumanth Nethi, Sarvani Kunapareddy, Sravya Ainapurapu, Raghu Ayinapurapu, Rajeswararao Ainapurapu. |
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